(3x-38)=(2x+16)

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Solution for (3x-38)=(2x+16) equation: 



(3x-38)=(2x+16)

We move all terms to the left:

(3x-38)-((2x+16))=0

We get rid of parentheses

3x-((2x+16))-38=0



We calculate terms in parentheses: -((2x+16)), so:

(2x+16)

We get rid of parentheses

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

3x-2x-16-38=0

We add all the numbers together, and all the variables

x-54=0

We move all terms containing x to the left, all other terms to the right

x=54

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