(3x-38)=(7x-95)

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Solution for (3x-38)=(7x-95) equation: 



(3x-38)=(7x-95)

We move all terms to the left:

(3x-38)-((7x-95))=0

We get rid of parentheses

3x-((7x-95))-38=0



We calculate terms in parentheses: -((7x-95)), so:

(7x-95)

We get rid of parentheses

7x-95

Back to the equation:

-(7x-95)



We get rid of parentheses

3x-7x+95-38=0

We add all the numbers together, and all the variables

-4x+57=0

We move all terms containing x to the left, all other terms to the right

-4x=-57

x=-57/-4

x=14+1/4

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