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(3x-4)(2+x)=0
We add all the numbers together, and all the variables
(3x-4)(x+2)=0
We multiply parentheses ..
(+3x^2+6x-4x-8)=0
We get rid of parentheses
3x^2+6x-4x-8=0
We add all the numbers together, and all the variables
3x^2+2x-8=0
a = 3; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·3·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*3}=\frac{8}{6} =1+1/3 $
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