(3x-4)(2-3x)=0

Solution for (3x-4)(2-3x)=0 equation:

(3x-4)(2-3x)=0

We add all the numbers together, and all the variables

(3x-4)(-3x+2)=0

We multiply parentheses ..

(-9x^2+6x+12x-8)=0

We get rid of parentheses

-9x^2+6x+12x-8=0

We add all the numbers together, and all the variables

-9x^2+18x-8=0

a = -9; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·(-9)·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*-9}=\frac{-24}{-18}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*-9}=\frac{-12}{-18}
=2/3
$