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(3x-4)(2x+6)=0
We multiply parentheses ..
(+6x^2+18x-8x-24)=0
We get rid of parentheses
6x^2+18x-8x-24=0
We add all the numbers together, and all the variables
6x^2+10x-24=0
a = 6; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·6·(-24)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*6}=\frac{-36}{12} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*6}=\frac{16}{12} =1+1/3 $
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