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(3x-4)(2x-1)-(3x+1)(x-3)=(3x-1)(x-1)
We move all terms to the left:
(3x-4)(2x-1)-(3x+1)(x-3)-((3x-1)(x-1))=0
We multiply parentheses ..
(+6x^2-3x-8x+4)-(3x+1)(x-3)-((3x-1)(x-1))=0
We calculate terms in parentheses: -((3x-1)(x-1)), so:We get rid of parentheses
(3x-1)(x-1)
We multiply parentheses ..
(+3x^2-3x-1x+1)
We get rid of parentheses
3x^2-3x-1x+1
We add all the numbers together, and all the variables
3x^2-4x+1
Back to the equation:
-(3x^2-4x+1)
6x^2-3x^2-3x-8x-(3x+1)(x-3)+4x+4-1=0
We multiply parentheses ..
6x^2-3x^2-(+3x^2-9x+x-3)-3x-8x+4x+4-1=0
We add all the numbers together, and all the variables
3x^2-(+3x^2-9x+x-3)-7x+3=0
We get rid of parentheses
3x^2-3x^2+9x-x-7x+3+3=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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