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(3x-4)(2x-5)/(2x-3)(3x-5)=1
We move all terms to the left:
(3x-4)(2x-5)/(2x-3)(3x-5)-(1)=0
Domain of the equation: (2x-3)(3x-5)!=0We multiply parentheses ..
We move all terms containing x to the left, all other terms to the right
2x-3)(3x!=5
x∈R
(+6x^2-15x-8x+20)/(2x-3)(3x-5)-1=0
We multiply all the terms by the denominator
(+6x^2-15x-8x+20)-1*(2x-3)(3x-5)=0
We get rid of parentheses
6x^2-15x-8x-1*(2x-3)(3x-5)+20=0
We multiply parentheses ..
6x^2-1*(+6x^2-10x-9x+15)-15x-8x+20=0
We add all the numbers together, and all the variables
6x^2-1*(+6x^2-10x-9x+15)-23x+20=0
We move all terms containing x to the left, all other terms to the right
6x^2-1*(+6x^2-10x-9x+15)-23x=-20
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