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(3x-4)(4x-3)=(6x-2)(2x-5)
We move all terms to the left:
(3x-4)(4x-3)-((6x-2)(2x-5))=0
We multiply parentheses ..
(+12x^2-9x-16x+12)-((6x-2)(2x-5))=0
We calculate terms in parentheses: -((6x-2)(2x-5)), so:We get rid of parentheses
(6x-2)(2x-5)
We multiply parentheses ..
(+12x^2-30x-4x+10)
We get rid of parentheses
12x^2-30x-4x+10
We add all the numbers together, and all the variables
12x^2-34x+10
Back to the equation:
-(12x^2-34x+10)
12x^2-12x^2-9x-16x+34x+12-10=0
We add all the numbers together, and all the variables
9x+2=0
We move all terms containing x to the left, all other terms to the right
9x=-2
x=-2/9
x=-2/9
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