(3x-4)(5x-12)-9(2x-7)=(3x-12)(5x-5)

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Solution for (3x-4)(5x-12)-9(2x-7)=(3x-12)(5x-5) equation: 



(3x-4)(5x-12)-9(2x-7)=(3x-12)(5x-5)

We move all terms to the left:

(3x-4)(5x-12)-9(2x-7)-((3x-12)(5x-5))=0

We multiply parentheses

(3x-4)(5x-12)-18x-((3x-12)(5x-5))+63=0

We multiply parentheses ..

(+15x^2-36x-20x+48)-18x-((3x-12)(5x-5))+63=0



We calculate terms in parentheses: -((3x-12)(5x-5)), so:

(3x-12)(5x-5)

We multiply parentheses ..

(+15x^2-15x-60x+60)

We get rid of parentheses

15x^2-15x-60x+60

We add all the numbers together, and all the variables

15x^2-75x+60

Back to the equation:

-(15x^2-75x+60)



We get rid of parentheses

15x^2-15x^2-36x-20x-18x+75x+48-60+63=0

We add all the numbers together, and all the variables

x+51=0

We move all terms containing x to the left, all other terms to the right

x=-51

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