(3x-4)(x+2)=200

Solution for (3x-4)(x+2)=200 equation:

(3x-4)(x+2)=200

We move all terms to the left:

(3x-4)(x+2)-(200)=0

We multiply parentheses ..

(+3x^2+6x-4x-8)-200=0

We get rid of parentheses

3x^2+6x-4x-8-200=0

We add all the numbers together, and all the variables

3x^2+2x-208=0

a = 3; b = 2; c = -208;
Δ = b2-4ac
Δ = 22-4·3·(-208)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-50}{2*3}=\frac{-52}{6}
=-8+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+50}{2*3}=\frac{48}{6}
=8
$