(3x-4)(x-11)=0

Solution for (3x-4)(x-11)=0 equation:

(3x-4)(x-11)=0

We multiply parentheses ..

(+3x^2-33x-4x+44)=0

We get rid of parentheses

3x^2-33x-4x+44=0

We add all the numbers together, and all the variables

3x^2-37x+44=0

a = 3; b = -37; c = +44;
Δ = b2-4ac
Δ = -372-4·3·44
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-29}{2*3}=\frac{8}{6}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+29}{2*3}=\frac{66}{6}
=11
$