(3x-4)*(2x-1)-10=6x*(x+4)

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Solution for (3x-4)*(2x-1)-10=6x*(x+4) equation: 



(3x-4)(2x-1)-10=6x(x+4)

We move all terms to the left:

(3x-4)(2x-1)-10-(6x(x+4))=0

We multiply parentheses ..

(+6x^2-3x-8x+4)-(6x(x+4))-10=0



We calculate terms in parentheses: -(6x(x+4)), so:

6x(x+4)

We multiply parentheses

6x^2+24x

Back to the equation:

-(6x^2+24x)



We get rid of parentheses

6x^2-6x^2-3x-8x-24x+4-10=0

We add all the numbers together, and all the variables

-35x-6=0

We move all terms containing x to the left, all other terms to the right

-35x=6

x=6/-35

x=-6/35

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