(3x-4)+(2x+2)+x=28

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Solution for (3x-4)+(2x+2)+x=28 equation: 



(3x-4)+(2x+2)+x=28

We move all terms to the left:

(3x-4)+(2x+2)+x-(28)=0

We add all the numbers together, and all the variables

x+(3x-4)+(2x+2)-28=0

We get rid of parentheses

x+3x+2x-4+2-28=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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