(3x-4)+(3x-4)+(3x)+(3x)=52

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Solution for (3x-4)+(3x-4)+(3x)+(3x)=52 equation: 



(3x-4)+(3x-4)+(3x)+(3x)=52

We move all terms to the left:

(3x-4)+(3x-4)+(3x)+(3x)-(52)=0

We add all the numbers together, and all the variables

6x+(3x-4)+(3x-4)-52=0

We get rid of parentheses

6x+3x+3x-4-4-52=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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