(3x-4)+(5x-7)=(13x+2)

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Solution for (3x-4)+(5x-7)=(13x+2) equation: 



(3x-4)+(5x-7)=(13x+2)

We move all terms to the left:

(3x-4)+(5x-7)-((13x+2))=0

We get rid of parentheses

3x+5x-((13x+2))-4-7=0



We calculate terms in parentheses: -((13x+2)), so:

(13x+2)

We get rid of parentheses

13x+2

Back to the equation:

-(13x+2)



We add all the numbers together, and all the variables

8x-(13x+2)-11=0

We get rid of parentheses

8x-13x-2-11=0

We add all the numbers together, and all the variables

-5x-13=0

We move all terms containing x to the left, all other terms to the right

-5x=13

x=13/-5

x=-2+3/5

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