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(3x-4)+(5x/2)=13
We move all terms to the left:
(3x-4)+(5x/2)-(13)=0
We add all the numbers together, and all the variables
(3x-4)+(+5x/2)-13=0
We get rid of parentheses
3x+5x/2-4-13=0
We multiply all the terms by the denominator
3x*2+5x-4*2-13*2=0
We add all the numbers together, and all the variables
5x+3x*2-34=0
Wy multiply elements
5x+6x-34=0
We add all the numbers together, and all the variables
11x-34=0
We move all terms containing x to the left, all other terms to the right
11x=34
x=34/11
x=3+1/11
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