(3x-4)+(6x+6)+(1x+20)=180

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Solution for (3x-4)+(6x+6)+(1x+20)=180 equation: 



(3x-4)+(6x+6)+(1x+20)=180

We move all terms to the left:

(3x-4)+(6x+6)+(1x+20)-(180)=0

We add all the numbers together, and all the variables

(3x-4)+(6x+6)+(x+20)-180=0

We get rid of parentheses

3x+6x+x-4+6+20-180=0

We add all the numbers together, and all the variables

10x-158=0

We move all terms containing x to the left, all other terms to the right

10x=158

x=158/10

x=15+4/5

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