(3x-4)+(6x-19)=(x+5)

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Solution for (3x-4)+(6x-19)=(x+5) equation: 



(3x-4)+(6x-19)=(x+5)

We move all terms to the left:

(3x-4)+(6x-19)-((x+5))=0

We get rid of parentheses

3x+6x-((x+5))-4-19=0



We calculate terms in parentheses: -((x+5)), so:

(x+5)

We get rid of parentheses

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

9x-(x+5)-23=0

We get rid of parentheses

9x-x-5-23=0

We add all the numbers together, and all the variables

8x-28=0

We move all terms containing x to the left, all other terms to the right

8x=28

x=28/8

x=3+1/2

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