(3x-4)+(x-2)=62

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Solution for (3x-4)+(x-2)=62 equation: 



(3x-4)+(x-2)=62

We move all terms to the left:

(3x-4)+(x-2)-(62)=0

We get rid of parentheses

3x+x-4-2-62=0

We add all the numbers together, and all the variables

4x-68=0

We move all terms containing x to the left, all other terms to the right

4x=68

x=68/4

x=17

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