(3x-4)+4x=2(7x-4)

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Solution for (3x-4)+4x=2(7x-4) equation: 



(3x-4)+4x=2(7x-4)

We move all terms to the left:

(3x-4)+4x-(2(7x-4))=0

We add all the numbers together, and all the variables

4x+(3x-4)-(2(7x-4))=0

We get rid of parentheses

4x+3x-(2(7x-4))-4=0



We calculate terms in parentheses: -(2(7x-4)), so:

2(7x-4)

We multiply parentheses

14x-8

Back to the equation:

-(14x-8)



We add all the numbers together, and all the variables

7x-(14x-8)-4=0

We get rid of parentheses

7x-14x+8-4=0

We add all the numbers together, and all the variables

-7x+4=0

We move all terms containing x to the left, all other terms to the right

-7x=-4

x=-4/-7

x=4/7

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