(3x-4)/(4x+3)=2

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Solution for (3x-4)/(4x+3)=2 equation: 



(3x-4)/(4x+3)=2

We move all terms to the left:

(3x-4)/(4x+3)-(2)=0



Domain of the equation: (4x+3)!=0

We move all terms containing x to the left, all other terms to the right

4x!=-3

x!=-3/4

x!=-3/4

x∈R



We multiply all the terms by the denominator


(3x-4)-2*(4x+3)=0

We multiply parentheses

(3x-4)-8x-6=0

We get rid of parentheses

3x-8x-4-6=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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