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(3x-4)/(5-2x)=5
We move all terms to the left:
(3x-4)/(5-2x)-(5)=0
Domain of the equation: (5-2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-2x!=-5
x!=-5/-2
x!=2+1/2
x∈R
(3x-4)/(-2x+5)-5=0
We multiply all the terms by the denominator
(3x-4)-5*(-2x+5)=0
We multiply parentheses
(3x-4)+10x-25=0
We get rid of parentheses
3x+10x-4-25=0
We add all the numbers together, and all the variables
13x-29=0
We move all terms containing x to the left, all other terms to the right
13x=29
x=29/13
x=2+3/13
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