(3x-4)/3=(5x+7)/2

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Solution for (3x-4)/3=(5x+7)/2 equation: 



(3x-4)/3=(5x+7)/2

We move all terms to the left:

(3x-4)/3-((5x+7)/2)=0

We calculate fractions


3x/()+(-((5x+7)*3)/()=0



We calculate terms in parentheses: +(-((5x+7)*3)/(), so:

-((5x+7)*3)/(

We multiply all the terms by the denominator


-((5x+7)*3)



We calculate terms in parentheses: -((5x+7)*3), so:

(5x+7)*3

We multiply parentheses

15x+21

Back to the equation:

-(15x+21)



We get rid of parentheses

-15x-21

Back to the equation:

+(-15x-21)



We get rid of parentheses

3x/()-15x-21=0

We multiply all the terms by the denominator


3x-15x*()-21*()=0

We add all the numbers together, and all the variables

3x-15x*()=0

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