(3x-4)/3=2x-(7/6)

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Solution for (3x-4)/3=2x-(7/6) equation: 



(3x-4)/3=2x-(7/6)

We move all terms to the left:

(3x-4)/3-(2x-(7/6))=0

We add all the numbers together, and all the variables

(3x-4)/3-(2x-(+7/6))=0

We calculate fractions


3x/()+(-(2x-(+7*3)/()=0



We calculate terms in parentheses: +(-(2x-(+7*3)/(), so:

-(2x-(+7*3)/(

We add all the numbers together, and all the variables

-(2x-21/(

We multiply all the terms by the denominator


-(2x-21

Back to the equation:

+(-(2x-21)



We multiply all the terms by the denominator


3x+((-(2x-21))*()=0



We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





We calculate terms in parentheses: +((-(2x-21))*(), so:

(-(2x-21))*(





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We calculate terms in parentheses: +((-(2x-21))*(), so:

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We calculate terms in parentheses: +((-(2x-21))*(), so:

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We calculate terms in parentheses: +((-(2x-21))*(), so:

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