(3x-4)/5-2/(x+3)=0

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Solution for (3x-4)/5-2/(x+3)=0 equation:


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(3*x-4)/5-(2/(x+3)) = 0

(3*x-4)/5-2*(x+3)^-1 = 0

(3*x-4)/5-2/(x+3) = 0

((3*x-4)*(x+3))/(5*(x+3))+(-2*5)/(5*(x+3)) = 0

(3*x-4)*(x+3)-2*5 = 0

3*x^2+5*x-22 = 0

3*x^2+5*x-22 = 0

3*x^2+5*x-22 = 0

DELTA = 5^2-(-22*3*4)

DELTA = 289

DELTA > 0

x = (289^(1/2)-5)/(2*3) or x = (-289^(1/2)-5)/(2*3)

x = 2 or x = -11/3

(x+11/3)*(x-2) = 0

((x+11/3)*(x-2))/(5*(x+3)) = 0

((x+11/3)*(x-2))/(5*(x+3)) = 0 // * 5*(x+3)

(x+11/3)*(x-2) = 0

( x+11/3 )

x+11/3 = 0 // - 11/3

x = -11/3

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -11/3, 2 }

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