(3x-4)/5=7(x-1)/2

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Solution for (3x-4)/5=7(x-1)/2 equation: 


x in (-oo:+oo)

(3*x-4)/5 = (7*(x-1))/2 // - (7*(x-1))/2

(3*x-4)/5-((7*(x-1))/2) = 0

(3*x-4)/5+(-7/2)*(x-1) = 0

(3*x-4)/5-7/2*(x-1) = 0

(3*x-4)/5+(-7/2*5*(x-1))/5 = 0

3*x-7/2*5*(x-1)-4 = 0

27/2-29/2*x = 0

(27/2-29/2*x)/5 = 0

(27/2-29/2*x)/5 = 0 // * 5

27/2-29/2*x = 0

27/2-29/2*x = 0 // - 27/2

-29/2*x = -27/2 // : -29/2

x = -27/2/(-29/2)

x = 27/29

x = 27/29

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