(3x-4)/6=(2x+1)/4

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Solution for (3x-4)/6=(2x+1)/4 equation: 


x in (-oo:+oo)

(3*x-4)/6 = (2*x+1)/4 // - (2*x+1)/4

(3*x-4)/6-((2*x+1)/4) = 0

(3*x-4)/6+(-1*(2*x+1))/4 = 0

(4*(3*x-4))/(4*6)+(-1*6*(2*x+1))/(4*6) = 0

4*(3*x-4)-1*6*(2*x+1) = 0

-22 = 0

-22/(4*6) = 0

-22/(4*6) = 0 // * 4*6

-22 = 0

x belongs to the empty set

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