(3x-4)/7=x-2

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Solution for (3x-4)/7=x-2 equation:



(3x-4)/7=x-2
We move all terms to the left:
(3x-4)/7-(x-2)=0
We get rid of parentheses
(3x-4)/7-x+2=0
We multiply all the terms by the denominator
(3x-4)-x*7+2*7=0
We add all the numbers together, and all the variables
(3x-4)-x*7+14=0
Wy multiply elements
(3x-4)-7x+14=0
We get rid of parentheses
3x-7x-4+14=0
We add all the numbers together, and all the variables
-4x+10=0
We move all terms containing x to the left, all other terms to the right
-4x=-10
x=-10/-4
x=2+1/2

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