(3x-4)/8=(x+2)/3

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Solution for (3x-4)/8=(x+2)/3 equation: 



(3x-4)/8=(x+2)/3

We move all terms to the left:

(3x-4)/8-((x+2)/3)=0

We calculate fractions


3x/()+(-((x+2)*8)/()=0



We calculate terms in parentheses: +(-((x+2)*8)/(), so:

-((x+2)*8)/(

We multiply all the terms by the denominator


-((x+2)*8)



We calculate terms in parentheses: -((x+2)*8), so:

(x+2)*8

We multiply parentheses

8x+16

Back to the equation:

-(8x+16)



We get rid of parentheses

-8x-16

Back to the equation:

+(-8x-16)



We get rid of parentheses

3x/()-8x-16=0

We multiply all the terms by the denominator


3x-8x*()-16*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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