(3x-4)=(x+28)

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Solution for (3x-4)=(x+28) equation: 



(3x-4)=(x+28)

We move all terms to the left:

(3x-4)-((x+28))=0

We get rid of parentheses

3x-((x+28))-4=0



We calculate terms in parentheses: -((x+28)), so:

(x+28)

We get rid of parentheses

x+28

Back to the equation:

-(x+28)



We get rid of parentheses

3x-x-28-4=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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