(3x-4)=2(2x+12)

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Solution for (3x-4)=2(2x+12) equation: 



(3x-4)=2(2x+12)

We move all terms to the left:

(3x-4)-(2(2x+12))=0

We get rid of parentheses

3x-(2(2x+12))-4=0



We calculate terms in parentheses: -(2(2x+12)), so:

2(2x+12)

We multiply parentheses

4x+24

Back to the equation:

-(4x+24)



We get rid of parentheses

3x-4x-24-4=0

We add all the numbers together, and all the variables

-1x-28=0

We move all terms containing x to the left, all other terms to the right

-x=28

x=28/-1

x=-28

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