(3x-4)=2(2x+12)

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Solution for (3x-4)=2(2x+12) equation:



(3x-4)=2(2x+12)
We move all terms to the left:
(3x-4)-(2(2x+12))=0
We get rid of parentheses
3x-(2(2x+12))-4=0
We calculate terms in parentheses: -(2(2x+12)), so:
2(2x+12)
We multiply parentheses
4x+24
Back to the equation:
-(4x+24)
We get rid of parentheses
3x-4x-24-4=0
We add all the numbers together, and all the variables
-1x-28=0
We move all terms containing x to the left, all other terms to the right
-x=28
x=28/-1
x=-28

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