(3x-40)=(2x+21)

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Solution for (3x-40)=(2x+21) equation: 



(3x-40)=(2x+21)

We move all terms to the left:

(3x-40)-((2x+21))=0

We get rid of parentheses

3x-((2x+21))-40=0



We calculate terms in parentheses: -((2x+21)), so:

(2x+21)

We get rid of parentheses

2x+21

Back to the equation:

-(2x+21)



We get rid of parentheses

3x-2x-21-40=0

We add all the numbers together, and all the variables

x-61=0

We move all terms containing x to the left, all other terms to the right

x=61

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