(3x-40)=(2x+23)

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Solution for (3x-40)=(2x+23) equation: 



(3x-40)=(2x+23)

We move all terms to the left:

(3x-40)-((2x+23))=0

We get rid of parentheses

3x-((2x+23))-40=0



We calculate terms in parentheses: -((2x+23)), so:

(2x+23)

We get rid of parentheses

2x+23

Back to the equation:

-(2x+23)



We get rid of parentheses

3x-2x-23-40=0

We add all the numbers together, and all the variables

x-63=0

We move all terms containing x to the left, all other terms to the right

x=63

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