(3x-41)/8=7

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Solution for (3x-41)/8=7 equation: 



(3x-41)/8=7

We move all terms to the left:

(3x-41)/8-(7)=0

We multiply all the terms by the denominator


(3x-41)-7*8=0

We add all the numbers together, and all the variables

(3x-41)-56=0

We get rid of parentheses

3x-41-56=0

We add all the numbers together, and all the variables

3x-97=0

We move all terms containing x to the left, all other terms to the right

3x=97

x=97/3

x=32+1/3

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