(3x-41)=(2x+12)

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Solution for (3x-41)=(2x+12) equation: 



(3x-41)=(2x+12)

We move all terms to the left:

(3x-41)-((2x+12))=0

We get rid of parentheses

3x-((2x+12))-41=0



We calculate terms in parentheses: -((2x+12)), so:

(2x+12)

We get rid of parentheses

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

3x-2x-12-41=0

We add all the numbers together, and all the variables

x-53=0

We move all terms containing x to the left, all other terms to the right

x=53

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