(3x-42)=(2x+11)

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Solution for (3x-42)=(2x+11) equation:



(3x-42)=(2x+11)
We move all terms to the left:
(3x-42)-((2x+11))=0
We get rid of parentheses
3x-((2x+11))-42=0
We calculate terms in parentheses: -((2x+11)), so:
(2x+11)
We get rid of parentheses
2x+11
Back to the equation:
-(2x+11)
We get rid of parentheses
3x-2x-11-42=0
We add all the numbers together, and all the variables
x-53=0
We move all terms containing x to the left, all other terms to the right
x=53

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