(3x-42)=(2x+11)

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Solution for (3x-42)=(2x+11) equation: 



(3x-42)=(2x+11)

We move all terms to the left:

(3x-42)-((2x+11))=0

We get rid of parentheses

3x-((2x+11))-42=0



We calculate terms in parentheses: -((2x+11)), so:

(2x+11)

We get rid of parentheses

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

3x-2x-11-42=0

We add all the numbers together, and all the variables

x-53=0

We move all terms containing x to the left, all other terms to the right

x=53

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