(3x-42)=(2x+21)

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Solution for (3x-42)=(2x+21) equation:



(3x-42)=(2x+21)
We move all terms to the left:
(3x-42)-((2x+21))=0
We get rid of parentheses
3x-((2x+21))-42=0
We calculate terms in parentheses: -((2x+21)), so:
(2x+21)
We get rid of parentheses
2x+21
Back to the equation:
-(2x+21)
We get rid of parentheses
3x-2x-21-42=0
We add all the numbers together, and all the variables
x-63=0
We move all terms containing x to the left, all other terms to the right
x=63

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