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(3x-49)=(2x)=(x+31)
We move all terms to the left:
(3x-49)-((2x))=0
determiningTheFunctionDomain (3x-49)-2x=0
We add all the numbers together, and all the variables
-2x+(3x-49)=0
We get rid of parentheses
-2x+3x-49=0
We add all the numbers together, and all the variables
x-49=0
We move all terms containing x to the left, all other terms to the right
x=49
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