(3x-5)(2x+10)=0

Solution for (3x-5)(2x+10)=0 equation:

(3x-5)(2x+10)=0

We multiply parentheses ..

(+6x^2+30x-10x-50)=0

We get rid of parentheses

6x^2+30x-10x-50=0

We add all the numbers together, and all the variables

6x^2+20x-50=0

a = 6; b = 20; c = -50;
Δ = b2-4ac
Δ = 202-4·6·(-50)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*6}=\frac{-60}{12}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*6}=\frac{20}{12}
=1+2/3
$