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(3x-5)(2x-25)=180
We move all terms to the left:
(3x-5)(2x-25)-(180)=0
We multiply parentheses ..
(+6x^2-75x-10x+125)-180=0
We get rid of parentheses
6x^2-75x-10x+125-180=0
We add all the numbers together, and all the variables
6x^2-85x-55=0
a = 6; b = -85; c = -55;
Δ = b2-4ac
Δ = -852-4·6·(-55)
Δ = 8545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-\sqrt{8545}}{2*6}=\frac{85-\sqrt{8545}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+\sqrt{8545}}{2*6}=\frac{85+\sqrt{8545}}{12} $
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