(3x-5)(2x-5)=(x-1)(6x-3)

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Solution for (3x-5)(2x-5)=(x-1)(6x-3) equation:



(3x-5)(2x-5)=(x-1)(6x-3)
We move all terms to the left:
(3x-5)(2x-5)-((x-1)(6x-3))=0
We multiply parentheses ..
(+6x^2-15x-10x+25)-((x-1)(6x-3))=0
We calculate terms in parentheses: -((x-1)(6x-3)), so:
(x-1)(6x-3)
We multiply parentheses ..
(+6x^2-3x-6x+3)
We get rid of parentheses
6x^2-3x-6x+3
We add all the numbers together, and all the variables
6x^2-9x+3
Back to the equation:
-(6x^2-9x+3)
We get rid of parentheses
6x^2-6x^2-15x-10x+9x+25-3=0
We add all the numbers together, and all the variables
-16x+22=0
We move all terms containing x to the left, all other terms to the right
-16x=-22
x=-22/-16
x=1+3/8

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