If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3x-5)(2x-6)=0
We multiply parentheses ..
(+6x^2-18x-10x+30)=0
We get rid of parentheses
6x^2-18x-10x+30=0
We add all the numbers together, and all the variables
6x^2-28x+30=0
a = 6; b = -28; c = +30;
Δ = b2-4ac
Δ = -282-4·6·30
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-8}{2*6}=\frac{20}{12} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+8}{2*6}=\frac{36}{12} =3 $
| 9c+24=60-9c | | 8x^2+2+12x=0 | | -4x+25=37 | | 4b-7=2b+9 | | -100+17x=4^2-23x | | 6(x)x=16 | | -100+17x=4 | | -4(v+17)+-14=-14 | | 3t/5=7/15 | | -7t=20-6t | | 4r+12r=-16 | | 23z-z=17 | | -8c-10=-13c | | 6b+16=5b | | -3=12/v | | 3=17-h | | (X)(1+x)(2+x)=1320 | | -0,2*x+15=3 | | 1.2^2x+1=1.2^9 | | -6x=-6x-4 | | 4–x3=1 | | (5y+2)(6+y)=0 | | 5(2x+3)+4(7x-5)-2(x-1=-39 | | 5x^2+4x=22 | | 2x−3=21 | | 7x+18=32-4x | | 3x+1=13−x | | 4x+34=91 | | r2-21r+80=0 | | 3t2+8t-8=0 | | X=(4x×40)+(3x×20) | | (7x+4)(3x+9)=(4x+3)(3x+5) |