(3x-5)(3x+5)=29

Solution for (3x-5)(3x+5)=29 equation:

(3x-5)(3x+5)=29

We move all terms to the left:

(3x-5)(3x+5)-(29)=0

We use the square of the difference formula

9x^2-25-29=0

We add all the numbers together, and all the variables

9x^2-54=0

a = 9; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·9·(-54)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*9}=\frac{0-18\sqrt{6}}{18}
=-\frac{18\sqrt{6}}{18}
=-\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*9}=\frac{0+18\sqrt{6}}{18}
=\frac{18\sqrt{6}}{18}
=\sqrt{6}
$