(3x-5)(x+1)=-6

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Solution for (3x-5)(x+1)=-6 equation: 



(3x-5)(x+1)=-6

We move all terms to the left:

(3x-5)(x+1)-(-6)=0

We add all the numbers together, and all the variables

(3x-5)(x+1)+6=0

We multiply parentheses ..

(+3x^2+3x-5x-5)+6=0

We get rid of parentheses

3x^2+3x-5x-5+6=0

We add all the numbers together, and all the variables

3x^2-2x+1=0

a = 3; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·3·1
Δ = -8
Delta is less than zero, so there is no solution for the equation

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