(3x-5)(x+4)=x(3x-7)

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Solution for (3x-5)(x+4)=x(3x-7) equation: 



(3x-5)(x+4)=x(3x-7)

We move all terms to the left:

(3x-5)(x+4)-(x(3x-7))=0

We multiply parentheses ..

(+3x^2+12x-5x-20)-(x(3x-7))=0



We calculate terms in parentheses: -(x(3x-7)), so:

x(3x-7)

We multiply parentheses

3x^2-7x

Back to the equation:

-(3x^2-7x)



We get rid of parentheses

3x^2-3x^2+12x-5x+7x-20=0

We add all the numbers together, and all the variables

14x-20=0

We move all terms containing x to the left, all other terms to the right

14x=20

x=20/14

x=1+3/7

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