(3x-5)(x-x-12)=0

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Solution for (3x-5)(x-x-12)=0 equation: 



(3x-5)(x-x-12)=0

We add all the numbers together, and all the variables

(3x-5)(-12)=0

We multiply parentheses ..

(-36x+60)=0

We get rid of parentheses

-36x+60=0

We move all terms containing x to the left, all other terms to the right

-36x=-60

x=-60/-36

x=1+2/3

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