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(3x-5)+(19-x)+(2x)=x
We move all terms to the left:
(3x-5)+(19-x)+(2x)-(x)=0
We add all the numbers together, and all the variables
(3x-5)+(-1x+19)+2x-x=0
We add all the numbers together, and all the variables
x+(3x-5)+(-1x+19)=0
We get rid of parentheses
x+3x-1x-5+19=0
We add all the numbers together, and all the variables
3x+14=0
We move all terms containing x to the left, all other terms to the right
3x=-14
x=-14/3
x=-4+2/3
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