(3x-5)+(2x+1)=16

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Solution for (3x-5)+(2x+1)=16 equation:


Simplifying
(3x + -5) + (2x + 1) = 16

Reorder the terms:
(-5 + 3x) + (2x + 1) = 16

Remove parenthesis around (-5 + 3x)
-5 + 3x + (2x + 1) = 16

Reorder the terms:
-5 + 3x + (1 + 2x) = 16

Remove parenthesis around (1 + 2x)
-5 + 3x + 1 + 2x = 16

Reorder the terms:
-5 + 1 + 3x + 2x = 16

Combine like terms: -5 + 1 = -4
-4 + 3x + 2x = 16

Combine like terms: 3x + 2x = 5x
-4 + 5x = 16

Solving
-4 + 5x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5x = 16 + 4

Combine like terms: -4 + 4 = 0
0 + 5x = 16 + 4
5x = 16 + 4

Combine like terms: 16 + 4 = 20
5x = 20

Divide each side by '5'.
x = 4

Simplifying
x = 4

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