(3x-5)+(3x-16)+19=180

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Solution for (3x-5)+(3x-16)+19=180 equation: 



(3x-5)+(3x-16)+19=180

We move all terms to the left:

(3x-5)+(3x-16)+19-(180)=0

We add all the numbers together, and all the variables

(3x-5)+(3x-16)-161=0

We get rid of parentheses

3x+3x-5-16-161=0

We add all the numbers together, and all the variables

6x-182=0

We move all terms containing x to the left, all other terms to the right

6x=182

x=182/6

x=30+1/3

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