(3x-5)+(x-1)=6x-27

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Solution for (3x-5)+(x-1)=6x-27 equation: 



(3x-5)+(x-1)=6x-27

We move all terms to the left:

(3x-5)+(x-1)-(6x-27)=0

We get rid of parentheses

3x+x-6x-5-1+27=0

We add all the numbers together, and all the variables

-2x+21=0

We move all terms containing x to the left, all other terms to the right

-2x=-21

x=-21/-2

x=10+1/2

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